What is the solution for (dy)/(dx)=2yx+yx^2,y(-3)=1 ?

The solution for (dy)/(dx)=2yx+yx^2,y(-3)=1 is y=e^{(x^3)/3+x^2}

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(dy)/(dx)=2yx+yx^2,y(-3)=1

\frac{d y}{d x} = 2 y x + y x^{2}, y (- 3) = 1

y = e^{\frac{x ^{3}}{3} + x^{2}}

Solution steps

\frac{d y}{d x} = 2 y x + y x^{2}

Solve separable ODE:

y = e^{\frac{x ^{3}}{3} + x^{2}}

y = e^{\frac{x ^{3}}{3} + x^{2}}

h (x) = \frac{1}{2 x}, at x = 4

x \to - 2 lim (2 x^{2})

\int x^{3} 5 + x^{2} d x

x + 7

\int_{0}^{4} 1 + 36 x d x

What is the solution for (dy)/(dx)=2yx+yx^2,y(-3)=1 ?
The solution for (dy)/(dx)=2yx+yx^2,y(-3)=1 is y=e^{(x^3)/3+x^2}