What is the derivative of x^x-100 ?

The derivative of x^x-100 is x^x(ln(x)+1)

What is the first derivative of x^x-100 ?

The first derivative of x^x-100 is x^x(ln(x)+1)

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\frac{d}{d x} (x^{x} - 100)

x^{x} (ln (x) + 1)

Solution steps

\frac{d}{d x} (x^{x} - 100)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{x}) - \frac{d}{d x} (100)

\frac{d}{d x} (x^{x}) = x^{x} (ln (x) + 1)

\frac{d}{d x} (100) = 0

= x^{x} (ln (x) + 1) - 0

Simplify

= x^{x} (ln (x) + 1)

y^{^{''}} - 8 y^{^{'}} + 15 y = - sin (2 t)

y^{^{''}} - 2 y^{^{'}} + 26 y = e^{x} sin (x)

x \to 0 lim (5 x^{2} - 4)

\frac{\partial}{\partial x} (e^{2 x + 8 y})

8 x

What is the derivative of x^x-100 ?
The derivative of x^x-100 is x^x(ln(x)+1)
What is the first derivative of x^x-100 ?
The first derivative of x^x-100 is x^x(ln(x)+1)