What is the derivative of-0.4x^3 ?

The derivative of-0.4x^3 is -1.2x^2

What is the first derivative of-0.4x^3 ?

The first derivative of-0.4x^3 is -1.2x^2

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\frac{d}{d x} (- 0.4 x^{3})

- 1.2 x^{2}

Solution steps

\frac{d}{d x} (- 0.4 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 0.4 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 0.4 \cdot 3 x^{3 - 1}

Simplify

= - 1.2 x^{2}

x \to 0 lim (\frac{5}{4} π - π)

x \to 0 lim (\frac{1}{2 - e ^{\frac{1}{x}}})

t y^{^{'}} + y = t^{3}, y (1) = - 2

\int_{\frac{1}{2}}^{1} (x^{- 3} - 3) d x

x \to 2 lim (x^{3} + 2 x^{2} + 1)

What is the derivative of-0.4x^3 ?
The derivative of-0.4x^3 is -1.2x^2
What is the first derivative of-0.4x^3 ?
The first derivative of-0.4x^3 is -1.2x^2