What is the derivative of y=(x^4)/(16) ?

The derivative of y=(x^4)/(16) is (x^3)/4

What is the first derivative of y=(x^4)/(16) ?

The first derivative of y=(x^4)/(16) is (x^3)/4

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derivative of

y = \frac{x ^{4}}{16}

\frac{x ^{3}}{4}

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{16})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{16} \frac{d}{d x} (x^{4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{16} \cdot 4 x^{4 - 1}

Simplify

\frac{1}{16} \cdot 4 x^{4 - 1} : \frac{x ^{3}}{4}

= \frac{x ^{3}}{4}

\int x (3 x - 5)^{10} d x

\int \frac{1}{( x ) ln ( x )} d x

\int \frac{8}{1 + 9 r ^{2}} d r

\frac{d}{d x} (\frac{( x ^{2} )}{x ^{2} + 4})

f (θ) = sec^{2} (θ)

What is the derivative of y=(x^4)/(16) ?
The derivative of y=(x^4)/(16) is (x^3)/4
What is the first derivative of y=(x^4)/(16) ?
The first derivative of y=(x^4)/(16) is (x^3)/4