What is the limit as x approaches 0 of 3/(e^x-1)-1/3 ?

The limit as x approaches 0 of 3/(e^x-1)-1/3 is diverges

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limit as x approaches 0 of 3/(e^x-1)-1/3

x \to 0 lim (\frac{3}{e ^{x} - 1} - \frac{1}{3})

diverges

Solution steps

x \to 0 lim (\frac{3}{e ^{x} - 1} - \frac{1}{3})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{3}{e ^{x} - 1} - \frac{1}{3}) = \infty

x \to 0 - lim (\frac{3}{e ^{x} - 1} - \frac{1}{3}) = - \infty

= diverges

\int - 4 cos (2 t + π) d t

\int \frac{4400 x}{4 x ^{2} + 320} d x

\frac{\partial}{\partial x} (8 y^{9} x^{7} - 7 y^{8} x^{6})

y^{^{'}} + 3 x^{2} y = sin (x) e^{- x^{3}}

x \to 3 lim (\frac{8 x + 7}{5 x + 7})

What is the limit as x approaches 0 of 3/(e^x-1)-1/3 ?
The limit as x approaches 0 of 3/(e^x-1)-1/3 is diverges