What is the limit as x approaches-infinity of 5x-2^x ?

The limit as x approaches-infinity of 5x-2^x is -infinity

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limit as x approaches-infinity of 5x-2^x

x \to - \infty lim (5 x - 2^{x})

- \infty

Solution steps

x \to - \infty lim (5 x - 2^{x})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to - \infty lim (5 x) - x \to - \infty lim (2^{x})

x \to - \infty lim (5 x) = - \infty

x \to - \infty lim (2^{x}) = 0

= - \infty - 0

Apply Infinity Property:

- \infty - c = - \infty

= - \infty

\frac{\partial}{\partial x} (\frac{9 y}{x ^{5}})

f (x) = 1 - 4 x

(t^{2} - 1) y^{^{'}} + 2 t y = 0

ln (\frac{x ^{3} ( 2 x + 1 )}{x ^{2} - 3})

\frac{\partial}{\partial t} (cos (t) - sin (t))

What is the limit as x approaches-infinity of 5x-2^x ?
The limit as x approaches-infinity of 5x-2^x is -infinity