What is (\partial)/(\partial x)(x+y+z) ?

The answer to (\partial)/(\partial x)(x+y+z) is 1

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(\partial)/(\partial x)(x+y+z)

\frac{\partial}{\partial x} (x + y + z)

1

Solution steps

\frac{\partial}{\partial x} (x + y + z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (y) + \frac{\partial}{\partial x} (z)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (z) = 0

= 1 + 0 + 0

Simplify

= 1

\frac{\partial}{\partial x} ((4 x - y^{2})^{\frac{3}{2}})

n = 1 \sum \infty \frac{6}{2 ^{n}}

\frac{\partial}{\partial x} (y (1 - x))

e^{- 3 s} \cdot \frac{5}{4 s ^{2} + 16}

4 x - x^{2} (1.3)

What is (\partial)/(\partial x)(x+y+z) ?
The answer to (\partial)/(\partial x)(x+y+z) is 1