What is the derivative of y= 1/(2x+1) ?

The derivative of y= 1/(2x+1) is -2/((2x+1)^2)

What is the first derivative of y= 1/(2x+1) ?

The first derivative of y= 1/(2x+1) is -2/((2x+1)^2)

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derivative of

y = \frac{1}{2 x + 1}

- \frac{2}{( 2 x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((2 x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

= - \frac{1}{( 2 x + 1 ) ^{2}} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= - \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2

Simplify

- \frac{1}{( 2 x + 1 ) ^{2}} \cdot 2 : - \frac{2}{( 2 x + 1 ) ^{2}}

= - \frac{2}{( 2 x + 1 ) ^{2}}

\int_{- 1}^{4} 2 - 2 x d x

\frac{cot ( x )}{1 + cot ( x )}

cos^{3} (π x)

x \to 1 + lim (2 x)

x^{2} \frac{d y}{d x} = 2 x y + y^{2}

What is the derivative of y= 1/(2x+1) ?
The derivative of y= 1/(2x+1) is -2/((2x+1)^2)
What is the first derivative of y= 1/(2x+1) ?
The first derivative of y= 1/(2x+1) is -2/((2x+1)^2)