What is the derivative of-x+4/x+1 ?

The derivative of-x+4/x+1 is -4/(x^2)-1

What is the first derivative of-x+4/x+1 ?

The first derivative of-x+4/x+1 is -4/(x^2)-1

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\frac{d}{d x} (- x + \frac{4}{x} + 1)

- \frac{4}{x ^{2}} - 1

Solution steps

\frac{d}{d x} (- x + \frac{4}{x} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d x}{d x} + \frac{d}{d x} (\frac{4}{x}) + \frac{d}{d x} (1)

\frac{d x}{d x} = 1

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

\frac{d}{d x} (1) = 0

= - 1 - \frac{4}{x ^{2}} + 0

Simplify

= - \frac{4}{x ^{2}} - 1

\frac{t ^{2} - 6 t}{( t - 3 ) ^{2}}

\int sec (t) (3 sec (t) + 5 tan (t)) d t

((x^{2}) 2^{x})^{3}

\frac{d}{d x} (150 - \frac{1}{40} (x - 50)^{2})

What is the derivative of-x+4/x+1 ?
The derivative of-x+4/x+1 is -4/(x^2)-1
What is the first derivative of-x+4/x+1 ?
The first derivative of-x+4/x+1 is -4/(x^2)-1