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Popular >

area y=x^2,y=4^{2/3}

Solution

area

y = x^{2}, y = 4^{\frac{2}{3}}

Solution

\frac{16}{3}

+1

Decimal Notation

5.33333 \dots

Solution steps

Apply the area formula:

\int_{- 4^{\frac{1}{3}}}^{4^{\frac{1}{3}}} x^{2} - 4^{\frac{2}{3}} d x

Solve

\int_{- 4^{\frac{1}{3}}}^{4^{\frac{1}{3}}} x^{2} - 4^{\frac{2}{3}} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Popular Examples

integral of (16x^3-8)sec^2(x^4-2x)

\int (16 x^{3} - 8) sec^{2} (x^{4} - 2 x) d x

derivative of sqrt(x)-1/5 x

\frac{d}{d x} (x - \frac{1}{5} x)

integral of sin(2u)

\int sin (2 u) d u

integral of-4/y

\int - \frac{4}{y} d y

derivative of y=sqrt(-7-3x)derivative of

y = - 7 - 3 x

Frequently Asked Questions (FAQ)

What is area y=x^2,y=4^{2/3} ?
The answer to area y=x^2,y=4^{2/3} is 16/3