What is laplacetransform sin(2pit) ?

The answer to laplacetransform sin(2pit) is (2pi)/(s^2+4pi^2)

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laplacetransform sin(2pit)

laplace transform

sin (2 π t)

\frac{2 π}{s ^{2} + 4 π ^{2}}

Solution steps

L {sin (2 π t)}

Use Laplace Transform table:

L {sin (a t)} = \frac{a}{s ^{2} + a ^{2}}

L {sin (2 π t)} = \frac{2 π}{s ^{2} + ( 2 π ) ^{2}}

= \frac{2 π}{s ^{2} + ( 2 π ) ^{2}}

= \frac{2 π}{s ^{2} + 4 π ^{2}}

x = 5 y^{2}, x = 54 - y^{2}

ln (x + 2) - 1

\int_{0}^{1} 3 e^{- 3 x} d x

\int \frac{1}{9 x ^{2} + 2} d x

\int (5 x + 6)^{- 1} d x

What is laplacetransform sin(2pit) ?
The answer to laplacetransform sin(2pit) is (2pi)/(s^2+4pi^2)