What is the solution for xy(dy)/(dx)=ln(x) ?

The solution for xy(dy)/(dx)=ln(x) is y=sqrt(ln^2(x)+c_{1)},y=-sqrt(ln^2(x)+c_{1)}

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xy(dy)/(dx)=ln(x)

x y \frac{d y}{d x} = ln (x)

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

Solution steps

x y \frac{d y}{d x} = ln (x)

Solve separable ODE:

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

\int \frac{x ^{2}}{( 1 - x ^{3} ) ^{2}} d x

\int (4 x^{2} - 16 x + 7)^{4} (x - 2) d x

n = 0 \sum \infty - 1^{2 n}

\int \frac{1}{81 + x ^{2}} d x

x \to 0 lim (0.1 ln (0.1))

What is the solution for xy(dy)/(dx)=ln(x) ?
The solution for xy(dy)/(dx)=ln(x) is y=sqrt(ln^2(x)+c_{1)},y=-sqrt(ln^2(x)+c_{1)}