What is the sum from k=0 to infinity of 5*3^k ?

The sum from k=0 to infinity of 5*3^k is diverges

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sum from k=0 to infinity of 5*3^k

k = 0 \sum \infty 5 \cdot 3^{k}

diverges

Solution steps

k = 0 \sum \infty 5 \cdot 3^{k}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 5 \cdot k = 0 \sum \infty 3^{k}

Apply Series Geometric Test:

diverges

= 5 diverges

= diverges

- \frac{4 x}{( x ^{2} - 1 ) ^{2}}

x \to 0 + lim (x^{2} - 2 x - 3)

\frac{\partial}{\partial x} (2 + y ln (4 + x y^{2}))

y = \frac{5}{x}, (4, \frac{5}{2})

\int \frac{e ^{x}}{e ^{x} + 1} d x

What is the sum from k=0 to infinity of 5*3^k ?
The sum from k=0 to infinity of 5*3^k is diverges