What is the derivative of 1+x^4 ?

The derivative of 1+x^4 is 4x^3

What is the first derivative of 1+x^4 ?

The first derivative of 1+x^4 is 4x^3

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\frac{d}{d x} (1 + x^{4})

4 x^{3}

Solution steps

\frac{d}{d x} (1 + x^{4})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (x^{4})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (x^{4}) = 4 x^{3}

= 0 + 4 x^{3}

Simplify

= 4 x^{3}

f (x) = \frac{x ^{2}}{x - 8}

\int 2 x^{2} y e^{x yz} d x

\frac{\partial}{\partial x} (- 2 x z)

\frac{d}{d x} (\frac{8 x - 1}{3 x + 8})

f (x) = \frac{7 x}{x + 4}, (3, 3)