What is the solution for N-0.0002N^2=(dN)/(dt) ?

The solution for N-0.0002N^2=(dN)/(dt) is N=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}

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N-0.0002N^2=(dN)/(dt)

N - 0.0002 N^{2} = \frac{d N}{d t}

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

Solution steps

N - 0.0002 N^{2} = \frac{d N}{d t}

Solve separable ODE:

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

N = - \frac{e ^{t + c_{1}}}{1 - 0.0002 e ^{t + c_{1}}}

x \to \infty + lim (x^{10})

\frac{\partial}{\partial x} (\frac{1}{cos ^{2} ( x )})

\int x 3 x^{2} - 1 d x

\frac{1}{( s ^{2} - 9 )}

What is the solution for N-0.0002N^2=(dN)/(dt) ?
The solution for N-0.0002N^2=(dN)/(dt) is N=-(e^{t+c_{1}})/(1-0.0002e^{t+c_{1)}}