What is area y=3(x+1),y=4(x+1),x=7 ?

The answer to area y=3(x+1),y=4(x+1),x=7 is 32

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area y=3(x+1),y=4(x+1),x=7

area

y = 3 (x + 1), y = 4 (x + 1), x = 7

32

Solution steps

Apply the area formula:

\int_{- 1}^{7} ∣ x + 1 ∣ d x

Solve

\int_{- 1}^{7} ∣ x + 1 ∣ d x : 32

The area is:

= 32

\frac{\partial}{\partial x} (e^{- 7 y} cos (π x))

\frac{d}{d x} (arcsec (x^{3}))

\int_{0}^{1} 7 cos (2 x) d x

\int 5 sin (5 θ) sin (θ) d θ

\int \frac{x}{x ^{2} + 5 x + 6} d x

What is area y=3(x+1),y=4(x+1),x=7 ?
The answer to area y=3(x+1),y=4(x+1),x=7 is 32