What is the integral from-infinity to 6 of 10xe^{2x} ?

The integral from-infinity to 6 of 10xe^{2x} is (55e^{12})/2

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integral from-infinity to 6 of 10xe^{2x}

\int_{- \infty}^{6} 10 x e^{2 x} d x

\frac{55 e ^{12}}{2}

Solution steps

\int_{- \infty}^{6} 10 x e^{2 x} d x

Compute the indefinite integral:

\int 10 x e^{2 x} d x = 5 e^{2 x} x - \frac{5}{2} e^{2 x} + C

Compute the boundaries:

\int_{- \infty}^{6} 10 x e^{2 x} d x = e^{12} \frac{55}{2} - 0

= e^{12} \frac{55}{2} - 0

Simplify

= \frac{55 e ^{12}}{2}

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What is the integral from-infinity to 6 of 10xe^{2x} ?
The integral from-infinity to 6 of 10xe^{2x} is (55e^{12})/2