What is (\partial)/(\partial x)(4/(xy)) ?

The answer to (\partial)/(\partial x)(4/(xy)) is -4/(x^2y)

Popular >

(\partial)/(\partial x)(4/(xy))

\frac{\partial}{\partial x} (\frac{4}{x y})

- \frac{4}{x ^{2} y}

Solution steps

\frac{\partial}{\partial x} (\frac{4}{x y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{4}{y} \frac{\partial}{\partial x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{4}{y} \frac{\partial}{\partial x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{4}{y} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{4}{y} (- 1 \cdot x^{- 1 - 1}) : - \frac{4}{x ^{2} y}

= - \frac{4}{x ^{2} y}

\frac{d y}{d t} = e^{2 (t)} - 3 y, y (0) = 1

\int_{- 1}^{0} 3 u + 4 d u

\int x^{9} x^{5} + 5 d x

y = (3 + 5 x)^{6} (3 x^{7} + 2)^{3}

\frac{d}{d x} (7 x sin (π x))

What is (\partial)/(\partial x)(4/(xy)) ?
The answer to (\partial)/(\partial x)(4/(xy)) is -4/(x^2y)