What is the derivative of e^pi-e^{pix}+2pi^2 ?

The derivative of e^pi-e^{pix}+2pi^2 is -pie^{pix}

What is the first derivative of e^pi-e^{pix}+2pi^2 ?

The first derivative of e^pi-e^{pix}+2pi^2 is -pie^{pix}

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\frac{d}{d x} (e^{π} - e^{π x} + 2 π^{2})

- π e^{π x}

Solution steps

\frac{d}{d x} (e^{π} - e^{π x} + 2 π^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (e^{π}) - \frac{d}{d x} (e^{π x}) + \frac{d}{d x} (2 π^{2})

\frac{d}{d x} (e^{π}) = 0

\frac{d}{d x} (e^{π x}) = e^{π x} π

\frac{d}{d x} (2 π^{2}) = 0

= 0 - e^{π x} π + 0

Simplify

= - π e^{π x}

y^{^{''}} + 2 y = sin (2 t)

tan (4 x)

e^{5 x}, 0

\int \frac{5}{x ^{2} - 10 x} d x

\int \frac{1}{3 - 2 x ^{2}} d x

What is the derivative of e^pi-e^{pix}+2pi^2 ?
The derivative of e^pi-e^{pix}+2pi^2 is -pie^{pix}
What is the first derivative of e^pi-e^{pix}+2pi^2 ?
The first derivative of e^pi-e^{pix}+2pi^2 is -pie^{pix}