What is (\partial)/(\partial x)((3x-2x^2)^3) ?

The answer to (\partial)/(\partial x)((3x-2x^2)^3) is 3(3x-2x^2)^2(3-4x)

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(\partial)/(\partial x)((3x-2x^2)^3)

\frac{\partial}{\partial x} ((3 x - 2 x^{2})^{3})

3 (3 x - 2 x^{2})^{2} (3 - 4 x)

Solution steps

\frac{\partial}{\partial x} ((3 x - 2 x^{2})^{3})

Apply the chain rule:

3 (3 x - 2 x^{2})^{2} \frac{\partial}{\partial x} (3 x - 2 x^{2})

= 3 (3 x - 2 x^{2})^{2} \frac{\partial}{\partial x} (3 x - 2 x^{2})

\frac{\partial}{\partial x} (3 x - 2 x^{2}) = 3 - 4 x

= 3 (3 x - 2 x^{2})^{2} (3 - 4 x)

\int (\frac{1 + x}{x})^{2} d x

\frac{d y}{d x} = \frac{1}{y ^{2}}

f (x) = 3 x - 12 x^{3}, at x = 0

\int 4 x 1 + 4 x^{2} d x

f (x) = 4 x^{2} e^{2 x^{2} + x - 1}

What is (\partial)/(\partial x)((3x-2x^2)^3) ?
The answer to (\partial)/(\partial x)((3x-2x^2)^3) is 3(3x-2x^2)^2(3-4x)