What is the tangent of sqrt(3x+7) ?

The tangent of sqrt(3x+7) is y= 3/(2sqrt(3a_{0)+7)}x+sqrt(3a_{0)+7}-(3a_{0})/(2sqrt(3a_{0)+7)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of sqrt(3x+7)

tangent of

3 x + 7

y = \frac{3}{2 3 a _{0} + 7} x + 3 a_{0} + 7 - \frac{3 a _{0}}{2 3 a _{0} + 7}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0} + 7)

Find the slope of

y = 3 x + 7 : \frac{d y}{d x} = \frac{3}{2 3 x + 7}

Compute the slope of

y = 3 x + 7

x = a_{0} : m = \frac{3}{2 3 a _{0} + 7}

Find the line with slope m=

\frac{3}{2 3 a _{0} + 7}

and passing through

(a_{0}, 3 a_{0} + 7) : y = \frac{3}{2 3 a _{0} + 7} x + 3 a_{0} + 7 - \frac{3 a _{0}}{2 3 a _{0} + 7}

y = \frac{3}{2 3 a _{0} + 7} x + 3 a_{0} + 7 - \frac{3 a _{0}}{2 3 a _{0} + 7}

\frac{\partial}{\partial x} (- e^{x} sin (y))

\frac{d}{d x} (e^{x} sin (6 x))

y = (- 4) + x^{2}, (1, - 3)

\int x^{2} x + 3 d x

cos (2 x)

What is the tangent of sqrt(3x+7) ?
The tangent of sqrt(3x+7) is y= 3/(2sqrt(3a_{0)+7)}x+sqrt(3a_{0)+7}-(3a_{0})/(2sqrt(3a_{0)+7)}