What is the sum from n=1 to infinity of (-1)^n 1/n ?

The sum from n=1 to infinity of (-1)^n 1/n is converges

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sum from n=1 to infinity of (-1)^n 1/n

n = 1 \sum \infty (- 1)^{n} \frac{1}{n}

converges

Solution steps

n = 1 \sum \infty (- 1)^{n} \frac{1}{n}

Apply Alternating Series Test:

converges

= converges

\frac{- u ^{2} + 8}{( u ^{2} + 8 ) ^{2}}

f (x) = e^{x} cosh (x)

x^{2} y^{^{''}} - 11 x y^{^{'}} + 36 y = 0

\frac{d}{d x} (x ln (x^{2} + x))

\int \frac{e ^{2 t}}{2} d t

What is the sum from n=1 to infinity of (-1)^n 1/n ?
The sum from n=1 to infinity of (-1)^n 1/n is converges