What is the first (log_{e}(x))^' ?

The first (log_{e}(x))^' is 1/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(log_{e}(x))^'

(lo g_{e} (x))^{^{'}}

\frac{1}{x}

Solution steps

(lo g_{e} (x))^{'}

Simplify

lo g_{e} (x) : ln (x)

= (ln (x))^{^{'}}

Apply the common derivative:

(ln (x))^{'} = \frac{1}{x}

= \frac{1}{x}

(- 3, 5), (3, 5)

y^{^{'}} = 2 x + 3

64 y^{^{''}} - 48 y^{^{'}} + 34 y = 0

\frac{d}{d x} (ln ((x^{2} + 1)^{20}))

\int \frac{x ^{2}}{( x + 1 ) ( x - 1 ) ^{2}} d x