What is the tangent of y=3x-4x^2,(-2,-22) ?

The tangent of y=3x-4x^2,(-2,-22) is y=19x+16

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tangent of y=3x-4x^2,(-2,-22)

tangent of

y = 3 x - 4 x^{2}, (- 2, - 22)

y = 19 x + 16

Solution steps

Find the slope of

y = 3 x - 4 x^{2} : \frac{d y}{d x} = 3 - 8 x

Compute the slope of

y = 3 x - 4 x^{2}

(- 2, - 22) : m = 19

Find the line with slope m=

19

and passing through

(- 2, - 22) : y = 19 x + 16

y = 19 x + 16

\frac{\partial}{\partial x} (e^{- x y} cos (y))

\frac{1}{s ^{2} ( s ^{2} + 3 s + 10 )}

\frac{d}{d x} (\frac{4 e ^{2 x} - 2 e ^{x} + 1}{2 e ^{2 x}})

\int 3 x^{2} e^{x} d x

\frac{\partial}{\partial x} (- 2 y csc^{3} (x))

What is the tangent of y=3x-4x^2,(-2,-22) ?
The tangent of y=3x-4x^2,(-2,-22) is y=19x+16