What is the integral of (x^2-y^2) ?

The integral of (x^2-y^2) is -y^2x+(x^3)/3+C

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integral of (x^2-y^2)

\int (x^{2} - y^{2}) d x

- y^{2} x + \frac{x ^{3}}{3} + C

Solution steps

\int x^{2} - y^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int y^{2} d x + \int x^{2} d x

\int y^{2} d x = y^{2} x

\int x^{2} d x = \frac{x ^{3}}{3}

= - y^{2} x + \frac{x ^{3}}{3}

Add a constant to the solution

= - y^{2} x + \frac{x ^{3}}{3} + C

x \to 1 lim (ln (5 x) + e^{x})

\int (\frac{1}{x ^{2} - 1}) d x

y^{^{''}} - 36 y = 0

\frac{d}{d t} (\frac{2 t}{1 + t ^{2}})

\int_{- 3}^{3} \frac{6}{x ^{2} + 9} d x

What is the integral of (x^2-y^2) ?
The integral of (x^2-y^2) is -y^2x+(x^3)/3+C