What is the tangent of y=(x^3-9x)^{10},(3,0) ?

The tangent of y=(x^3-9x)^{10},(3,0) is y=0

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tangent of y=(x^3-9x)^{10},(3,0)

tangent of

y = (x^{3} - 9 x)^{10}, (3, 0)

y = 0

Solution steps

Find the slope of

y = (x^{3} - 9 x)^{10} : \frac{d y}{d x} = 10 (x^{3} - 9 x)^{9} (3 x^{2} - 9)

Compute the slope of

y = (x^{3} - 9 x)^{10}

(3, 0) : m = 0

Find the line with slope m=

0

and passing through

(3, 0) : y = 0

y = 0

y = 3 x^{3} - 3 x, (- 4, 0)

\int_{0}^{3} (5 - \frac{5}{3} x)^{2} d x

(- 10.6) (- 5.8)

\frac{d}{d x} (5 x - x^{2})

x \to 3 lim (7)

What is the tangent of y=(x^3-9x)^{10},(3,0) ?
The tangent of y=(x^3-9x)^{10},(3,0) is y=0