What is (\partial)/(\partial x)(-sin(4x)) ?

The answer to (\partial)/(\partial x)(-sin(4x)) is -cos(4x)*4

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(\partial)/(\partial x)(-sin(4x))

\frac{\partial}{\partial x} (- sin (4 x))

- cos (4 x) \cdot 4

Solution steps

\frac{\partial}{\partial x} (- sin (4 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial x} (sin (4 x))

Apply the chain rule:

cos (4 x) \frac{\partial}{\partial x} (4 x)

= cos (4 x) \frac{\partial}{\partial x} (4 x)

\frac{\partial}{\partial x} (4 x) = 4

= - cos (4 x) \cdot 4

f (x) = x^{2} + 2 x + 3

\int 4 \frac{x}{( x + 2 ) ^{(\frac{1}{4})}} d x

x \to 1 - lim (3^{\frac{1}{x}})

\frac{\partial}{\partial y} (e^{x} + cos (y + z))

(x^{2} + 4) y^{^{'}} + 3 x y = x

What is (\partial)/(\partial x)(-sin(4x)) ?
The answer to (\partial)/(\partial x)(-sin(4x)) is -cos(4x)*4