What is the derivative of (e^{4x})^2 ?

The derivative of (e^{4x})^2 is e^{8x}*8

What is the first derivative of (e^{4x})^2 ?

The first derivative of (e^{4x})^2 is e^{8x}*8

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derivative of

(e^{4 x})^{2}

e^{8 x} \cdot 8

Solution steps

\frac{d}{d x} ((e^{4 x})^{2})

Simplify

(e^{4 x})^{2} : e^{8 x}

= \frac{d}{d x} (e^{8 x})

Apply the chain rule:

e^{8 x} \frac{d}{d x} (8 x)

= e^{8 x} \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= e^{8 x} \cdot 8

y^{^{'}} + 2 y = 50 e^{- 10 t}

\frac{d}{d x} (\frac{- x}{x ^{2} + 1})

\frac{4}{s ^{2} ( s + 1 )}

y^{^{''}} + 7 y^{^{'}} + 10 y = 13 t e^{5 t}

\int x^{3} (1 - x) d x

What is the derivative of (e^{4x})^2 ?
The derivative of (e^{4x})^2 is e^{8x}*8
What is the first derivative of (e^{4x})^2 ?
The first derivative of (e^{4x})^2 is e^{8x}*8