What is the derivative of ln(x^2+1) ?

The derivative of ln(x^2+1) is (2x)/(x^2+1)

What is the first derivative of ln(x^2+1) ?

The first derivative of ln(x^2+1) is (2x)/(x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

ln (x^{2} + 1)

\frac{2 x}{x ^{2} + 1}

Solution steps

\frac{d}{d x} (ln (x^{2} + 1))

Apply the chain rule:

\frac{1}{x ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

= \frac{1}{x ^{2} + 1} \frac{d}{d x} (x^{2} + 1)

\frac{d}{d x} (x^{2} + 1) = 2 x

= \frac{1}{x ^{2} + 1} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 1} \cdot 2 x : \frac{2 x}{x ^{2} + 1}

= \frac{2 x}{x ^{2} + 1}

\int 2 x sin (x) e^{x} d x

\frac{e ^{- 4 s}}{2 s - 1}

x^{2} sin (x)

x \to \frac{1}{5} + lim (\frac{x}{10 x - 2})

What is the derivative of ln(x^2+1) ?
The derivative of ln(x^2+1) is (2x)/(x^2+1)
What is the first derivative of ln(x^2+1) ?
The first derivative of ln(x^2+1) is (2x)/(x^2+1)