What is the d/(dt)(cos(3t)) ?

The d/(dt)(cos(3t)) is -sin(3t)*3

What is the first d/(dt)(cos(3t)) ?

The first d/(dt)(cos(3t)) is -sin(3t)*3

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\frac{d}{d t} (cos (3 t))

- sin (3 t) \cdot 3

Solution steps

\frac{d}{d t} (cos (3 t))

Apply the chain rule:

- sin (3 t) \frac{d}{d t} (3 t)

= - sin (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= - sin (3 t) \cdot 3

n = 0 \sum \infty \frac{1}{n \cdot ln ( n )}

\int e^{- 5 x} tan (e^{- 5 x}) d x

\frac{d}{d x} (1 + sec (x))

\frac{d}{d x} (- x^{5} - 6 x^{4} - 14 x^{3} - 16 x^{2} - 9 x - 2)

\frac{\partial ^{2}}{\partial x \partial y} (ln (3 + x^{2} y^{2}))