What is (\partial)/(\partial x)(1+3x^2y^2) ?

The answer to (\partial)/(\partial x)(1+3x^2y^2) is 6xy^2

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(\partial)/(\partial x)(1+3x^2y^2)

\frac{\partial}{\partial x} (1 + 3 x^{2} y^{2})

6 x y^{2}

Solution steps

\frac{\partial}{\partial x} (1 + 3 x^{2} y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (3 x^{2} y^{2})

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (3 x^{2} y^{2}) = 6 y^{2} x

= 0 + 6 y^{2} x

Simplify

= 6 x y^{2}

\frac{\partial}{\partial x} (x^{2} y^{3} e^{x y})

x \to \infty lim (\frac{9 x - x ^{2} - 7 x ^{4}}{x ^{3} + 12 x})

\int \frac{( x ^{6} e ^{x} )}{x} d x

\int (1 - x) x^{3} (x - 2)^{2} d x

x y^{^{'}} - 2 y = 2 x^{2} - 2 x - 2

What is (\partial)/(\partial x)(1+3x^2y^2) ?
The answer to (\partial)/(\partial x)(1+3x^2y^2) is 6xy^2