What is the derivative of 6sqrt(x)+9 ?

The derivative of 6sqrt(x)+9 is 3/(sqrt(x))

What is the first derivative of 6sqrt(x)+9 ?

The first derivative of 6sqrt(x)+9 is 3/(sqrt(x))

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derivative of

6 x + 9

\frac{3}{x}

Solution steps

\frac{d}{d x} (6 x + 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 x) + \frac{d}{d x} (9)

\frac{d}{d x} (6 x) = \frac{3}{x}

\frac{d}{d x} (9) = 0

= \frac{3}{x} + 0

Simplify

= \frac{3}{x}

\int \frac{e ^{x} - 1}{e ^{x} + 1} d x

x \to 1 + lim (x^{2} + 1)

\int \frac{x}{x ^{3} - 1} d x

\frac{\partial}{\partial x} (\frac{2 x ^{2} y}{2 + x ^{2} y ^{2}})

What is the derivative of 6sqrt(x)+9 ?
The derivative of 6sqrt(x)+9 is 3/(sqrt(x))
What is the first derivative of 6sqrt(x)+9 ?
The first derivative of 6sqrt(x)+9 is 3/(sqrt(x))