What is the derivative of (x^4/4-(x^3)/3-3x^2+4) ?

The derivative of (x^4/4-(x^3)/3-3x^2+4) is x^3-x^2-6x

What is the first derivative of (x^4/4-(x^3)/3-3x^2+4) ?

The first derivative of (x^4/4-(x^3)/3-3x^2+4) is x^3-x^2-6x

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\frac{d}{d x} (\frac{x ^{4}}{4} - \frac{x ^{3}}{3} - 3 x^{2} + 4)

x^{3} - x^{2} - 6 x

Solution steps

\frac{d}{d x} (\frac{x ^{4}}{4} - \frac{x ^{3}}{3} - 3 x^{2} + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{4}}{4}) - \frac{d}{d x} (\frac{x ^{3}}{3}) - \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4)

\frac{d}{d x} (\frac{x ^{4}}{4}) = x^{3}

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= x^{3} - x^{2} - 6 x + 0

Simplify

= x^{3} - x^{2} - 6 x

\int (4 - 3 x)^{7} d x

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\frac{d y}{d x} - \frac{4}{x} y = y^{5} \frac{1}{x ^{8}}

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What is the derivative of (x^4/4-(x^3)/3-3x^2+4) ?
The derivative of (x^4/4-(x^3)/3-3x^2+4) is x^3-x^2-6x
What is the first derivative of (x^4/4-(x^3)/3-3x^2+4) ?
The first derivative of (x^4/4-(x^3)/3-3x^2+4) is x^3-x^2-6x