What is the tangent of 7/x ?

The tangent of 7/x is y=-7/(a_{0)^2}x+(14)/(a_{0)}

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tangent of 7/x

tangent of

\frac{7}{x}

y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{7}{a _{0}})

Find the slope of

y = \frac{7}{x} : \frac{d y}{d x} = - \frac{7}{x ^{2}}

Compute the slope of

y = \frac{7}{x}

x = a_{0} : m = - \frac{7}{a _{0}^{2}}

Find the line with slope m=

- \frac{7}{a _{0}^{2}}

and passing through

(a_{0}, \frac{7}{a _{0}}) : y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

y = - \frac{7}{a _{0}^{2}} x + \frac{14}{a _{0}}

\frac{d}{d x} (cosh (cos (x)))

x \to 0 lim (\frac{sin ( 2 x )}{arcsin ( x )})

\frac{d}{d x} ((x^{2} + 5)^{7})

f (x) = ln (e^{- x} + x e^{- x})

\frac{3 t ^{5} - 1}{x ^{2} + 2}