What is the integral of+(54)/(1-cos(9x)) ?

The integral of+(54)/(1-cos(9x)) is -6cot((9x)/2)+C

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integral of+(54)/(1-cos(9x))

\int + \frac{54}{1 - cos ( 9 x )} d x

- 6 cot (\frac{9 x}{2}) + C

Solution steps

\int \frac{54}{1 - cos ( 9 x )} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 54 \cdot \int \frac{1}{1 - cos ( 9 x )} d x

Apply u-substitution

: \int \frac{1}{9 ( 1 - cos ( u ) )} d u

= 54 \cdot \int \frac{1}{9 ( 1 - cos ( u ) )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 54 \cdot \frac{1}{9} \cdot \int \frac{1}{1 - cos ( u )} d u

Apply u-substitution

: \int \frac{1}{v ^{2}} d v

= 54 \cdot \frac{1}{9} \cdot \int \frac{1}{v ^{2}} d v

Apply the Power Rule

: - \frac{1}{v}

= 54 \cdot \frac{1}{9} (- \frac{1}{v})

Substitute back

= 54 \cdot \frac{1}{9} (- \frac{1}{tan ( \frac{9 x}{2} )})

Simplify

54 \cdot \frac{1}{9} (- \frac{1}{tan ( \frac{9 x}{2} )}) : - 6 cot (\frac{9 x}{2})

= - 6 cot (\frac{9 x}{2})

Add a constant to the solution

= - 6 cot (\frac{9 x}{2}) + C

x^{2} + 3, at (x = 1)

\frac{s ^{2} - 1}{s ^{4} + 3 s ^{2} + 2}

\int \frac{1}{2 x ^{2} + 2} d x

- t

\frac{\partial}{\partial x} (- 2 s t)

What is the integral of+(54)/(1-cos(9x)) ?
The integral of+(54)/(1-cos(9x)) is -6cot((9x)/2)+C