What is the derivative of g(x)=sqrt(3-x) ?

The derivative of g(x)=sqrt(3-x) is -1/(2sqrt(3-x))

What is the first derivative of g(x)=sqrt(3-x) ?

The first derivative of g(x)=sqrt(3-x) is -1/(2sqrt(3-x))

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derivative of

g (x) = 3 - x

- \frac{1}{2 3 - x}

Solution steps

\frac{d}{d x} (3 - x)

Apply the chain rule:

\frac{1}{2 3 - x} \frac{d}{d x} (3 - x)

= \frac{1}{2 3 - x} \frac{d}{d x} (3 - x)

\frac{d}{d x} (3 - x) = - 1

= \frac{1}{2 3 - x} (- 1)

Simplify

= - \frac{1}{2 3 - x}

\frac{\partial}{\partial x} (4 x + 16 y)

7 e^{- x} + e^{3 x}

x^{^{''}} + 3 x^{^{'}} = 3 e^{(- 3 t)}

\frac{\partial}{\partial x} (\frac{x y}{x y + 4})

\frac{3 s e ^{- 3 s}}{4 s ^{2} + 64}

What is the derivative of g(x)=sqrt(3-x) ?
The derivative of g(x)=sqrt(3-x) is -1/(2sqrt(3-x))
What is the first derivative of g(x)=sqrt(3-x) ?
The first derivative of g(x)=sqrt(3-x) is -1/(2sqrt(3-x))