What is laplacetransform-5t^2\delta(t-1) ?

The answer to laplacetransform-5t^2\delta(t-1) is -5e^{-s}

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laplacetransform-5t^2\delta(t-1)

laplace transform

- 5 t^{2} δ (t - 1)

- 5 e^{- s}

Solution steps

L {- 5 t^{2} δ (t - 1)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {t^{2} δ (t - 1)}

L {t^{2} δ (t - 1)} : e^{- s}

= - 5 e^{- s}

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What is laplacetransform-5t^2\delta(t-1) ?
The answer to laplacetransform-5t^2\delta(t-1) is -5e^{-s}