What is the derivative of 3500(1-1/50 x^2) ?

The derivative of 3500(1-1/50 x^2) is -140(1-x/(50))

What is the first derivative of 3500(1-1/50 x^2) ?

The first derivative of 3500(1-1/50 x^2) is -140(1-x/(50))

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\frac{d}{d x} (3500 (1 - \frac{1}{50} x)^{2})

- 140 (1 - \frac{x}{50})

Solution steps

\frac{d}{d x} (3500 (1 - \frac{1}{50} x)^{2})

Simplify

3500 (1 - \frac{1}{50} x)^{2} : 3500 (1 - \frac{x}{50})^{2}

= \frac{d}{d x} (3500 (1 - \frac{x}{50})^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3500 \frac{d}{d x} ((1 - \frac{x}{50})^{2})

Apply the chain rule:

2 (1 - \frac{x}{50}) \frac{d}{d x} (1 - \frac{x}{50})

= 2 (1 - \frac{x}{50}) \frac{d}{d x} (1 - \frac{x}{50})

\frac{d}{d x} (1 - \frac{x}{50}) = - \frac{1}{50}

= 3500 \cdot 2 (1 - \frac{x}{50}) (- \frac{1}{50})

Simplify

3500 \cdot 2 (1 - \frac{x}{50}) (- \frac{1}{50}) : - 140 (1 - \frac{x}{50})

= - 140 (1 - \frac{x}{50})

\int (5 x + 3) d x

y ln (x) (x d y + y d x) = (x y ln (x) - y) d y

\int (2 x - 1) e^{- x} d x

f (x) = (6 x - 2)^{\frac{1}{3}}, at x = 1

y^{^{'}} - t^{2} y = 0

What is the derivative of 3500(1-1/50 x^2) ?
The derivative of 3500(1-1/50 x^2) is -140(1-x/(50))
What is the first derivative of 3500(1-1/50 x^2) ?
The first derivative of 3500(1-1/50 x^2) is -140(1-x/(50))