What is the integral from 2 to infinity of 1/(x^5) ?

The integral from 2 to infinity of 1/(x^5) is 1/64

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integral from 2 to infinity of 1/(x^5)

\int_{2}^{\infty} \frac{1}{x ^{5}} d x

\frac{1}{64}

Decimal Notation

0.015625

Solution steps

\int_{2}^{\infty} \frac{1}{x ^{5}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{5}} d x = - \frac{1}{4 x ^{4}} + C

Compute the boundaries:

\int_{2}^{\infty} \frac{1}{x ^{5}} d x = 0 - (- \frac{1}{64})

= 0 - (- \frac{1}{64})

Simplify

= \frac{1}{64}

x^{2}, x + 6

\int x e^{\frac{x ^{2}}{2}} d x

\frac{d}{d x} (2 x \cdot e^{3 x})

x \to π lim (3 arctan (x))

\frac{d}{d x} (\frac{2 x ^{2} - 2 x + 1}{x})

What is the integral from 2 to infinity of 1/(x^5) ?
The integral from 2 to infinity of 1/(x^5) is 1/64