What is laplacetransform e^{2-t} ?

The answer to laplacetransform e^{2-t} is (e^2)/(s+1)

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laplacetransform e^{2-t}

laplace transform

e^{2 - t}

\frac{e ^{2}}{s + 1}

Solution steps

L {e^{2 - t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{2} L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= e^{2} \frac{1}{s + 1}

Refine

e^{2} \frac{1}{s + 1} : \frac{e ^{2}}{s + 1}

= \frac{e ^{2}}{s + 1}

(t - 4)^{2}

\frac{\partial}{\partial y} (x^{3})

(x^{4} + y^{4}) d x - x y^{3} d y = 0

\frac{d y}{d x} - tan (x) - \frac{1}{x} = 0

\int \frac{2}{( x ^{2} - 1 ) ^{2}} d x

What is laplacetransform e^{2-t} ?
The answer to laplacetransform e^{2-t} is (e^2)/(s+1)