What is the solution for x^2(dy)/(dx)+2xy=5y^4 ?

The solution for x^2(dy)/(dx)+2xy=5y^4 is y=\sqrt[3]{(7x)/(15+7c_{1)x^7}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2(dy)/(dx)+2xy=5y^4

x^{2} \frac{d y}{d x} + 2 x y = 5 y^{4}

Solution steps

x^{2} \frac{d y}{d x} + 2 x y = 5 y^{4}

Solve Bernoulli ODE:

\int \frac{x}{4} d x

\frac{\partial}{\partial y} (\frac{x}{y})

x \to 2 lim (\frac{( x - 2 )}{x})

(((- 3)^{^{'}})^{4})^{^{'}}

\frac{d}{d x} (\frac{x ^{4} + 7 x ^{3} + 14 x ^{2}}{x + 3})

What is the solution for x^2(dy)/(dx)+2xy=5y^4 ?
The solution for x^2(dy)/(dx)+2xy=5y^4 is y=\sqrt[3]{(7x)/(15+7c_{1)x^7}}