What is the solution for (dy)/(dx)+y=e^{-x} ?

The solution for (dy)/(dx)+y=e^{-x} is y= x/(e^x)+(c_{1})/(e^x)

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(dy)/(dx)+y=e^{-x}

\frac{d y}{d x} + y = e^{- x}

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

Solution steps

\frac{d y}{d x} + y = e^{- x}

Solve linear ODE:

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

y = \frac{x}{e ^{x}} + \frac{c _{1}}{e ^{x}}

\frac{5 s}{s ^{2} ( s ^{2} + 16 )}

n = 0 \sum \infty n sin (\frac{1}{n})

y = 3 x^{3} - 3 x, (1, 0)

x \to 2 lim (x^{2} - 4 x + 3)

\frac{\partial}{\partial x} (x 1 - x^{2})

What is the solution for (dy)/(dx)+y=e^{-x} ?
The solution for (dy)/(dx)+y=e^{-x} is y= x/(e^x)+(c_{1})/(e^x)