What is (\partial)/(\partial y)(2x+y-8) ?

The answer to (\partial)/(\partial y)(2x+y-8) is 1

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(\partial)/(\partial y)(2x+y-8)

\frac{\partial}{\partial y} (2 x + y - 8)

1

Solution steps

\frac{\partial}{\partial y} (2 x + y - 8)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x) + \frac{\partial}{\partial y} (y) - \frac{\partial}{\partial y} (8)

\frac{\partial}{\partial y} (2 x) = 0

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} (8) = 0

= 0 + 1 - 0

Simplify

= 1

tan (x^{2})

\int_{1}^{\infty} 1

\frac{d}{d x} (\frac{1}{2} (3 x^{2} + x)^{- 3})

f (x) = x^{4} sin (2 x)

\frac{d}{d x} ((x + 2) (\frac{300}{x} + 4))

What is (\partial)/(\partial y)(2x+y-8) ?
The answer to (\partial)/(\partial y)(2x+y-8) is 1