What is the integral from 0 to 2pi of sin(x)+cos(x) ?

The integral from 0 to 2pi of sin(x)+cos(x) is 0

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integral from 0 to 2pi of sin(x)+cos(x)

\int_{0}^{2 π} sin (x) + cos (x) d x

0

Solution steps

\int_{0}^{2 π} sin (x) + cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2 π} sin (x) d x + \int_{0}^{2 π} cos (x) d x

\int_{0}^{2 π} sin (x) d x = 0

\int_{0}^{2 π} cos (x) d x = 0

= 0 + 0

Simplify

= 0

x \to 5 lim (\frac{5}{( x - 5 ) ^{2}})

\int \frac{x + 3}{x ^{4} + 9 x ^{2}} d x

\frac{d}{d x} (sin (x) ln (6 x))

x \to 0 + lim (x^{7} ln (x))

x \to 0 + lim (x ln (x^{7}))

What is the integral from 0 to 2pi of sin(x)+cos(x) ?
The integral from 0 to 2pi of sin(x)+cos(x) is 0