What is the derivative of y=2x^4+3x-3 ?

The derivative of y=2x^4+3x-3 is 8x^3+3

What is the first derivative of y=2x^4+3x-3 ?

The first derivative of y=2x^4+3x-3 is 8x^3+3

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derivative of

y = 2 x^{4} + 3 x - 3

8 x^{3} + 3

Solution steps

\frac{d}{d x} (2 x^{4} + 3 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) + \frac{d}{d x} (3 x) - \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (3) = 0

= 8 x^{3} + 3 - 0

Simplify

= 8 x^{3} + 3

\frac{d}{d x} (2 + cos (2 x))

\frac{s}{( s ^{2} + 49 ) ( s ^{2} + 1 )}

\frac{x}{x ^{2} - 9}

\frac{d}{d y} (sinh (y))

x^{2} + 11 x y + y^{2} = 11

What is the derivative of y=2x^4+3x-3 ?
The derivative of y=2x^4+3x-3 is 8x^3+3
What is the first derivative of y=2x^4+3x-3 ?
The first derivative of y=2x^4+3x-3 is 8x^3+3