What is the integral of e^{2y}-ycos(xy) ?

The integral of e^{2y}-ycos(xy) is e^{2y}x-sin(yx)+C

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integral of e^{2y}-ycos(xy)

\int e^{2 y} - y cos (x y) d x

e^{2 y} x - sin (y x) + C

Solution steps

\int e^{2 y} - y cos (x y) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int e^{2 y} d x - \int cos (y x) y d x

\int e^{2 y} d x = e^{2 y} x

\int cos (y x) y d x = sin (y x)

= e^{2 y} x - sin (y x)

Add a constant to the solution

= e^{2 y} x - sin (y x) + C

\frac{d}{d x} (4.9 x^{2})

\frac{\partial}{\partial x} (ln (\frac{x - 2}{3}))

x \to 7 lim (\frac{x - 7}{∣ x - 7 ∣})

x \to 0 lim (x^{2} + 3 x + 1)

\frac{d y}{d x} + y^{9} x + 5 y = 0

What is the integral of e^{2y}-ycos(xy) ?
The integral of e^{2y}-ycos(xy) is e^{2y}x-sin(yx)+C