What is the (x^2sin(x^2))^' ?

The (x^2sin(x^2))^' is 2xsin(x^2)+2x^3cos(x^2)

What is the first (x^2sin(x^2))^' ?

The first (x^2sin(x^2))^' is 2xsin(x^2)+2x^3cos(x^2)

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(x^{2} sin (x^{2}))^{^{'}}

2 x sin (x^{2}) + 2 x^{3} cos (x^{2})

Solution steps

(x^{2} sin (x^{2}))^{'}

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = sin (x^{2})

= (x^{2})^{^{'}} sin (x^{2}) + (sin (x^{2}))^{^{'}} x^{2}

(x^{2})^{'} = 2 x

(sin (x^{2}))^{'} = cos (x^{2}) \cdot 2 x

= 2 x sin (x^{2}) + cos (x^{2}) \cdot 2 x x^{2}

cos (x^{2}) \cdot 2 x x^{2} = 2 x^{3} cos (x^{2})

= 2 x sin (x^{2}) + 2 x^{3} cos (x^{2})

\int \frac{( 4 x ^{3} - 6 x ^{4} )}{2 x ^{6}} d x

f (x) = 2 x^{4} + 3 x - 3, (2, 35)

9 a^{2} + 8 a - 56

t = 0 \sum \infty \frac{1}{t ^{0.51}}

What is the (x^2sin(x^2))^' ?
The (x^2sin(x^2))^' is 2xsin(x^2)+2x^3cos(x^2)
What is the first (x^2sin(x^2))^' ?
The first (x^2sin(x^2))^' is 2xsin(x^2)+2x^3cos(x^2)