What is the derivative of 1+1/(2x) ?

The derivative of 1+1/(2x) is -1/(2x^2)

What is the first derivative of 1+1/(2x) ?

The first derivative of 1+1/(2x) is -1/(2x^2)

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\frac{d}{d x} (1 + \frac{1}{2 x})

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (1 + \frac{1}{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (\frac{1}{2 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (\frac{1}{2 x}) = - \frac{1}{2 x ^{2}}

= 0 - \frac{1}{2 x ^{2}}

Simplify

= - \frac{1}{2 x ^{2}}

y = \frac{x - 5}{x + 5}

x^{2} y^{^{'}} + x y = 6

\frac{d}{d x} ((2 x + 1)^{2} 3 (2 x + 1) + 10)

\frac{1}{s ^{2} - s + 1}

n = 0 \sum \infty 7 (\frac{2}{3})^{n}

What is the derivative of 1+1/(2x) ?
The derivative of 1+1/(2x) is -1/(2x^2)
What is the first derivative of 1+1/(2x) ?
The first derivative of 1+1/(2x) is -1/(2x^2)