What is the solution for y^'+x(y^2+y)=0,y(2)=1 ?

The solution for y^'+x(y^2+y)=0,y(2)=1 is y= 1/(2e^{\frac{x^2){2}-2}-1}

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y^'+x(y^2+y)=0,y(2)=1

y^{^{'}} + x (y^{2} + y) = 0, y (2) = 1

y = \frac{1}{2 e ^{\frac{x ^{2}}{2} - 2} - 1}

Solution steps

y^{'} (x) + x (y^{2} + y) = 0

Solve Bernoulli ODE:

y = \frac{1}{2 e ^{\frac{x ^{2}}{2} - 2} - 1}

y = \frac{1}{2 e ^{\frac{x ^{2}}{2} - 2} - 1}

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What is the solution for y^'+x(y^2+y)=0,y(2)=1 ?
The solution for y^'+x(y^2+y)=0,y(2)=1 is y= 1/(2e^{\frac{x^2){2}-2}-1}