What is the tangent of f(x)= 1/(2+3x),(1, 1/5) ?

The tangent of f(x)= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25

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tangent of f(x)= 1/(2+3x),(1, 1/5)

tangent of

f (x) = \frac{1}{2 + 3 x}, (1, \frac{1}{5})

y = - \frac{3}{25} x + \frac{8}{25}

Solution steps

Find the slope of

f (x) = \frac{1}{2 + 3 x} : \frac{df ( x )}{d x} = - \frac{3}{( 2 + 3 x ) ^{2}}

Compute the slope of

f (x) = \frac{1}{2 + 3 x}

(1, \frac{1}{5}) : m = - \frac{3}{25}

Find the line with slope m=

- \frac{3}{25}

and passing through

(1, \frac{1}{5}) : y = - \frac{3}{25} x + \frac{8}{25}

y = - \frac{3}{25} x + \frac{8}{25}

e^{- 2 t} t

e^{x}, - 4

\frac{\partial}{\partial y} ((2 x + 3 y)^{10})

\frac{1 - 3 t}{4 + t}

\int \frac{1}{7 x + 1} d x

What is the tangent of f(x)= 1/(2+3x),(1, 1/5) ?
The tangent of f(x)= 1/(2+3x),(1, 1/5) is y=-3/25 x+8/25